Distance Calculator

Distance from Warrensburg to Sikeston

Distance between Warrensburg and Sikeston is 420 kilometers (261 miles).
Driving distance from Warrensburg to Sikeston is 559 kilometers (347 miles).

air 420 km
air 261 miles
car 559 km
car 347 miles

Distance Map Between Warrensburg and Sikeston

Warrensburg, Jefferson City, United StatesSikeston, Jefferson City, United States = 261 miles = 420 km.

How far is it between Warrensburg and Sikeston

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Sikeston is located in United States with (36.8767,-89.5879) coordinates. The calculated flying distance from Warrensburg to Sikeston is equal to 261 miles which is equal to 420 km.

If you want to go by car, the driving distance between Warrensburg and Sikeston is 558.82 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 04 hours 59 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 139 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
Sikeston 36.8767, -89.5879 36° 52´ 36.1920'' N
89° 35´ 16.2960'' W

Estimated Travel Time Between Warrensburg and Sikeston

Average SpeedTravel Time
30 mph (48 km/h) 11 hours 38 minutes
40 mph (64 km/h) 08 hours 43 minutes
50 mph (80 km/h) 06 hours 59 minutes
60 mph (97 km/h) 05 hours 45 minutes
70 mph (112 km/h) 04 hours 59 minutes
75 mph (120 km/h) 04 hours 39 minutes
Please Share Your Comments