Distance from Warrensburg to Columbia

Distance between Warrensburg and Columbia is 123 kilometers (77 miles).
Driving distance from Warrensburg to Columbia is 152 kilometers (95 miles).

123 km

77 miles

152 km

95 miles

Distance Map Between Warrensburg and Columbia

Warrensburg, Jefferson City, United States ↔ Columbia, Jefferson City, United States = 77 miles = 123 km.

How far is it between Warrensburg and Columbia

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Columbia is located in United States with (38.9517,-92.3341) coordinates. The calculated flying distance from Warrensburg to Columbia is equal to 77 miles which is equal to 123 km.

If you want to go by car, the driving distance between Warrensburg and Columbia is 152.36 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 21 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 29 km.

City/Place	Latitude and Longitude	GPS Coordinates
Warrensburg	38.7628, -93.7361	38° 45´ 46.0440'' N 93° 44´ 9.7800'' W
Columbia	38.9517, -92.3341	38° 57´ 6.1560'' N 92° 20´ 2.6520'' W

Estimated Travel Time Between Warrensburg and Columbia

Average Speed	Travel Time
30 mph (48 km/h)	03 hours 10 minutes
40 mph (64 km/h)	02 hours 22 minutes
50 mph (80 km/h)	01 hours 54 minutes
60 mph (97 km/h)	01 hours 34 minutes
70 mph (112 km/h)	01 hours 21 minutes
75 mph (120 km/h)	01 hours 16 minutes

Warrensburg, Jefferson City, United States

Related Distances from Warrensburg

Cities	Distance
Warrensburg to Nixa	223 km
Warrensburg to Clayton 2	340 km
Warrensburg to Florissant	335 km
Warrensburg to St Louis	349 km
Warrensburg to Lemay	356 km

Columbia, Jefferson City, United States

Related Distances to Columbia

Cities	Distance
Rolla to Columbia 2	151 km
Hazelwood to Columbia 2	180 km
Hannibal to Columbia 2	157 km
Raytown to Columbia 2	192 km
Springfield to Columbia 2	270 km