Distance from Warrensburg to Arnold

Distance between Warrensburg and Arnold is 294 kilometers (183 miles).
Driving distance from Warrensburg to Arnold is 356 kilometers (221 miles).

294 km

183 miles

356 km

221 miles

Distance Map Between Warrensburg and Arnold

Warrensburg, Jefferson City, United States ↔ Arnold, Jefferson City, United States = 183 miles = 294 km.

How far is it between Warrensburg and Arnold

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Arnold is located in United States with (38.4328,-90.3776) coordinates. The calculated flying distance from Warrensburg to Arnold is equal to 183 miles which is equal to 294 km.

If you want to go by car, the driving distance between Warrensburg and Arnold is 355.6 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 03 hours 10 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 62 km.

City/Place	Latitude and Longitude	GPS Coordinates
Warrensburg	38.7628, -93.7361	38° 45´ 46.0440'' N 93° 44´ 9.7800'' W
Arnold	38.4328, -90.3776	38° 25´ 58.1880'' N 90° 22´ 39.4320'' W

Estimated Travel Time Between Warrensburg and Arnold

Average Speed	Travel Time
30 mph (48 km/h)	07 hours 24 minutes
40 mph (64 km/h)	05 hours 33 minutes
50 mph (80 km/h)	04 hours 26 minutes
60 mph (97 km/h)	03 hours 39 minutes
70 mph (112 km/h)	03 hours 10 minutes
75 mph (120 km/h)	02 hours 57 minutes

Warrensburg, Jefferson City, United States

Related Distances from Warrensburg

Cities	Distance
Warrensburg to Overland	334 km
Warrensburg to Saint Joseph	186 km
Warrensburg to Arnold 3	356 km
Warrensburg to Sedalia	48 km
Warrensburg to Raymore	80 km

Arnold, Jefferson City, United States

Related Distances to Arnold

Cities	Distance
Joplin to Arnold 3	451 km
Spanish Lake to Arnold 3	51 km
Saint Charles to Arnold 3	55 km
Saint Joseph to Arnold 3	493 km
Creve Coeur to Arnold 3	35 km