Distance Calculator

Distance from Warrensburg to O'Fallon

Distance between Warrensburg and O'Fallon is 263 kilometers (164 miles).
Driving distance from Warrensburg to O'Fallon is 298 kilometers (185 miles).

air 263 km
air 164 miles
car 298 km
car 185 miles

Distance Map Between Warrensburg and O'Fallon

Warrensburg, Jefferson City, United StatesO'Fallon, Jefferson City, United States = 164 miles = 263 km.

How far is it between Warrensburg and O'Fallon

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and O'Fallon is located in United States with (38.8106,-90.6999) coordinates. The calculated flying distance from Warrensburg to O'Fallon is equal to 164 miles which is equal to 263 km.

If you want to go by car, the driving distance between Warrensburg and O'Fallon is 297.94 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 02 hours 39 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 35 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
O'Fallon 38.8106, -90.6999 38° 48´ 38.1960'' N
90° 41´ 59.4600'' W

Estimated Travel Time Between Warrensburg and O'Fallon

Average SpeedTravel Time
30 mph (48 km/h) 06 hours 12 minutes
40 mph (64 km/h) 04 hours 39 minutes
50 mph (80 km/h) 03 hours 43 minutes
60 mph (97 km/h) 03 hours 04 minutes
70 mph (112 km/h) 02 hours 39 minutes
75 mph (120 km/h) 02 hours 28 minutes
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