Distance Calculator

Distance from Warrensburg to Liberty

Distance between Warrensburg and Liberty is 80 kilometers (50 miles).
Driving distance from Warrensburg to Liberty is 105 kilometers (65 miles).

air 80 km
air 50 miles
car 105 km
car 65 miles

Distance Map Between Warrensburg and Liberty

Warrensburg, Jefferson City, United StatesLiberty, Jefferson City, United States = 50 miles = 80 km.

How far is it between Warrensburg and Liberty

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Liberty is located in United States with (39.2461,-94.4191) coordinates. The calculated flying distance from Warrensburg to Liberty is equal to 50 miles which is equal to 80 km.

If you want to go by car, the driving distance between Warrensburg and Liberty is 104.71 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 56 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 25 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
Liberty 39.2461, -94.4191 39° 14´ 45.9960'' N
94° 25´ 8.8320'' W

Estimated Travel Time Between Warrensburg and Liberty

Average SpeedTravel Time
30 mph (48 km/h) 02 hours 10 minutes
40 mph (64 km/h) 01 hours 38 minutes
50 mph (80 km/h) 01 hours 18 minutes
60 mph (97 km/h) 01 hours 04 minutes
70 mph (112 km/h) 00 hours 56 minutes
75 mph (120 km/h) 00 hours 52 minutes
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