Distance Calculator

Distance from Tinley Park to Libertyville

Distance between Tinley Park and Libertyville is 80 kilometers (50 miles).
Driving distance from Tinley Park to Libertyville is 103 kilometers (64 miles).

air 80 km
air 50 miles
car 103 km
car 64 miles

Distance Map Between Tinley Park and Libertyville

Tinley Park, Springfield, United StatesLibertyville, Springfield, United States = 50 miles = 80 km.

How far is it between Tinley Park and Libertyville

Tinley Park is located in United States with (41.5734,-87.7845) coordinates and Libertyville is located in United States with (42.2831,-87.9531) coordinates. The calculated flying distance from Tinley Park to Libertyville is equal to 50 miles which is equal to 80 km.

If you want to go by car, the driving distance between Tinley Park and Libertyville is 102.57 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 54 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 23 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Tinley Park 41.5734, -87.7845 41° 34´ 24.1320'' N
87° 47´ 4.1640'' W
Libertyville 42.2831, -87.9531 42° 16´ 59.0880'' N
87° 57´ 11.2680'' W

Estimated Travel Time Between Tinley Park and Libertyville

Average SpeedTravel Time
30 mph (48 km/h) 02 hours 08 minutes
40 mph (64 km/h) 01 hours 36 minutes
50 mph (80 km/h) 01 hours 16 minutes
60 mph (97 km/h) 01 hours 03 minutes
70 mph (112 km/h) 00 hours 54 minutes
75 mph (120 km/h) 00 hours 51 minutes
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