Distance Calculator

Distance from Warrensburg to Saint Peters

Distance between Warrensburg and Saint Peters is 270 kilometers (167 miles).
Driving distance from Warrensburg to Saint Peters is 305 kilometers (189 miles).

air 270 km
air 167 miles
car 305 km
car 189 miles

Distance Map Between Warrensburg and Saint Peters

Warrensburg, Jefferson City, United StatesSaint Peters, Jefferson City, United States = 167 miles = 270 km.

How far is it between Warrensburg and Saint Peters

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Saint Peters is located in United States with (38.8003,-90.6265) coordinates. The calculated flying distance from Warrensburg to Saint Peters is equal to 167 miles which is equal to 270 km.

If you want to go by car, the driving distance between Warrensburg and Saint Peters is 304.61 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 02 hours 43 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 35 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
Saint Peters 38.8003, -90.6265 38° 48´ 1.1880'' N
90° 37´ 35.4360'' W

Estimated Travel Time Between Warrensburg and Saint Peters

Average SpeedTravel Time
30 mph (48 km/h) 06 hours 20 minutes
40 mph (64 km/h) 04 hours 45 minutes
50 mph (80 km/h) 03 hours 48 minutes
60 mph (97 km/h) 03 hours 08 minutes
70 mph (112 km/h) 02 hours 43 minutes
75 mph (120 km/h) 02 hours 32 minutes
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