Distance Calculator

Distance from Warrensburg to Guadalupe

Distance between Warrensburg and Guadalupe is 1578 kilometers (980 miles).
Driving distance from Warrensburg to Guadalupe is 1747 kilometers (1086 miles).

air 1578 km
air 980 miles
car 1747 km
car 1086 miles

Distance Map Between Warrensburg and Guadalupe

Warrensburg, Jefferson City, United StatesGuadalupe, Monterrey, Mexico = 980 miles = 1578 km.

How far is it between Warrensburg and Guadalupe

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Guadalupe is located in Mexico with (25.6768,-100.2565) coordinates. The calculated flying distance from Warrensburg to Guadalupe is equal to 980 miles which is equal to 1578 km.

If you want to go by car, the driving distance between Warrensburg and Guadalupe is 1747.06 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 15 hours 35 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 169 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
Guadalupe 25.6768, -100.2565 25° 40´ 36.4080'' N
100° 15´ 23.2560'' W

Estimated Travel Time Between Warrensburg and Guadalupe

Average SpeedTravel Time
30 mph (48 km/h) 36 hours 23 minutes
40 mph (64 km/h) 27 hours 17 minutes
50 mph (80 km/h) 21 hours 50 minutes
60 mph (97 km/h) 18 hours 00 minutes
70 mph (112 km/h) 15 hours 35 minutes
75 mph (120 km/h) 14 hours 33 minutes
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