Distance Calculator

Distance from Warrensburg to Apodaca

Distance between Warrensburg and Apodaca is 1566 kilometers (973 miles).
Driving distance from Warrensburg to Apodaca is 1733 kilometers (1077 miles).

air 1566 km
air 973 miles
car 1733 km
car 1077 miles

Distance Map Between Warrensburg and Apodaca

Warrensburg, Jefferson City, United StatesApodaca, Monterrey, Mexico = 973 miles = 1566 km.

How far is it between Warrensburg and Apodaca

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Apodaca is located in Mexico with (25.7598,-100.1629) coordinates. The calculated flying distance from Warrensburg to Apodaca is equal to 973 miles which is equal to 1566 km.

If you want to go by car, the driving distance between Warrensburg and Apodaca is 1733.07 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 15 hours 28 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 167 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
Apodaca 25.7598, -100.1629 25° 45´ 35.1360'' N
100° 9´ 46.3320'' W

Estimated Travel Time Between Warrensburg and Apodaca

Average SpeedTravel Time
30 mph (48 km/h) 36 hours 06 minutes
40 mph (64 km/h) 27 hours 04 minutes
50 mph (80 km/h) 21 hours 39 minutes
60 mph (97 km/h) 17 hours 52 minutes
70 mph (112 km/h) 15 hours 28 minutes
75 mph (120 km/h) 14 hours 26 minutes
Please Share Your Comments