Distance Calculator

Distance from Warrensburg to East Independence

Distance between Warrensburg and East Independence is 65 kilometers (40 miles).
Driving distance from Warrensburg to East Independence is 90 kilometers (56 miles).

air 65 km
air 40 miles
car 90 km
car 56 miles

Distance Map Between Warrensburg and East Independence

Warrensburg, Jefferson City, United StatesEast Independence, Jefferson City, United States = 40 miles = 65 km.

How far is it between Warrensburg and East Independence

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and East Independence is located in United States with (39.0956,-94.3552) coordinates. The calculated flying distance from Warrensburg to East Independence is equal to 40 miles which is equal to 65 km.

If you want to go by car, the driving distance between Warrensburg and East Independence is 89.53 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 47 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 25 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
East Independence 39.0956, -94.3552 39° 5´ 44.0160'' N
94° 21´ 18.8280'' W

Estimated Travel Time Between Warrensburg and East Independence

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 51 minutes
40 mph (64 km/h) 01 hours 23 minutes
50 mph (80 km/h) 01 hours 07 minutes
60 mph (97 km/h) 00 hours 55 minutes
70 mph (112 km/h) 00 hours 47 minutes
75 mph (120 km/h) 00 hours 44 minutes
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