Distance Calculator

Distance from Teaneck to Sayreville

Distance between Teaneck and Sayreville is 57 kilometers (35 miles).
Driving distance from Teaneck to Sayreville is 73 kilometers (45 miles).

air 57 km
air 35 miles
car 73 km
car 45 miles

Distance Map Between Teaneck and Sayreville

Teaneck, Trenton, United StatesSayreville, Trenton, United States = 35 miles = 57 km.

How far is it between Teaneck and Sayreville

Teaneck is located in United States with (40.8976,-74.016) coordinates and Sayreville is located in United States with (40.4593,-74.361) coordinates. The calculated flying distance from Teaneck to Sayreville is equal to 35 miles which is equal to 57 km.

If you want to go by car, the driving distance between Teaneck and Sayreville is 72.81 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 39 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 16 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Teaneck 40.8976, -74.016 40° 53´ 51.3600'' N
74° 0´ 57.4920'' W
Sayreville 40.4593, -74.361 40° 27´ 33.3720'' N
74° 21´ 39.5280'' W

Estimated Travel Time Between Teaneck and Sayreville

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 31 minutes
40 mph (64 km/h) 01 hours 08 minutes
50 mph (80 km/h) 00 hours 54 minutes
60 mph (97 km/h) 00 hours 45 minutes
70 mph (112 km/h) 00 hours 39 minutes
75 mph (120 km/h) 00 hours 36 minutes
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