Distance Calculator

Distance from Randolph to Sayreville

Distance between Randolph and Sayreville is 47 kilometers (29 miles).
Driving distance from Randolph to Sayreville is 75 kilometers (47 miles).

air 47 km
air 29 miles
car 75 km
car 47 miles

Distance Map Between Randolph and Sayreville

Randolph, Trenton, United StatesSayreville, Trenton, United States = 29 miles = 47 km.

How far is it between Randolph and Sayreville

Randolph is located in United States with (40.8483,-74.5815) coordinates and Sayreville is located in United States with (40.4593,-74.361) coordinates. The calculated flying distance from Randolph to Sayreville is equal to 29 miles which is equal to 47 km.

If you want to go by car, the driving distance between Randolph and Sayreville is 75.33 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 40 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 28 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Randolph 40.8483, -74.5815 40° 50´ 53.8440'' N
74° 34´ 53.3280'' W
Sayreville 40.4593, -74.361 40° 27´ 33.3720'' N
74° 21´ 39.5280'' W

Estimated Travel Time Between Randolph and Sayreville

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 34 minutes
40 mph (64 km/h) 01 hours 10 minutes
50 mph (80 km/h) 00 hours 56 minutes
60 mph (97 km/h) 00 hours 46 minutes
70 mph (112 km/h) 00 hours 40 minutes
75 mph (120 km/h) 00 hours 37 minutes
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