Distance from Teaneck to Sayreville Junction
Distance between Teaneck and Sayreville Junction is 55 kilometers (34 miles).
Driving distance from Teaneck to Sayreville Junction is 66 kilometers (41 miles).
55 km
34 miles
66 km
41 miles
Distance Map Between Teaneck and Sayreville Junction
Teaneck, Trenton, United States ↔ Sayreville Junction, Trenton, United States = 34 miles = 55 km.
How far is it between Teaneck and Sayreville Junction
Teaneck is located in United States with (40.8976,-74.016) coordinates and Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates. The calculated flying distance from Teaneck to Sayreville Junction is equal to 34 miles which is equal to 55 km.
If you want to go by car, the driving distance between Teaneck and Sayreville Junction is 66.06 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 35 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 11 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Teaneck | 40.8976, -74.016 | 40° 53´ 51.3600'' N 74° 0´ 57.4920'' W |
| Sayreville Junction | 40.4654, -74.3304 | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
Estimated Travel Time Between Teaneck and Sayreville Junction
| Average Speed | Travel Time |
|---|---|
| 30 mph (48 km/h) | 01 hours 22 minutes |
| 40 mph (64 km/h) | 01 hours 01 minutes |
| 50 mph (80 km/h) | 00 hours 49 minutes |
| 60 mph (97 km/h) | 00 hours 40 minutes |
| 70 mph (112 km/h) | 00 hours 35 minutes |
| 75 mph (120 km/h) | 00 hours 33 minutes |
Related Distances from Teaneck
| Cities | Distance |
|---|---|
| Teaneck to Mahwah | 26 km |
| Teaneck to Jackson 3 | 162 km |
| Teaneck to Williamstown | 182 km |
| Teaneck to Roselle 2 | 45 km |
| Teaneck to Jersey City | 33 km |