Distance Calculator

Distance from Searcy to Rogers

Distance between Searcy and Rogers is 246 kilometers (153 miles).
Driving distance from Searcy to Rogers is 369 kilometers (229 miles).

air 246 km
air 153 miles
car 369 km
car 229 miles

Distance Map Between Searcy and Rogers

Searcy, Little Rock, United StatesRogers, Little Rock, United States = 153 miles = 246 km.

How far is it between Searcy and Rogers

Searcy is located in United States with (35.2506,-91.7363) coordinates and Rogers is located in United States with (36.332,-94.1185) coordinates. The calculated flying distance from Searcy to Rogers is equal to 153 miles which is equal to 246 km.

If you want to go by car, the driving distance between Searcy and Rogers is 369 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 03 hours 17 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 123 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Searcy 35.2506, -91.7363 35° 15´ 2.3040'' N
91° 44´ 10.5000'' W
Rogers 36.332, -94.1185 36° 19´ 55.2720'' N
94° 7´ 6.7440'' W

Estimated Travel Time Between Searcy and Rogers

Average SpeedTravel Time
30 mph (48 km/h) 07 hours 41 minutes
40 mph (64 km/h) 05 hours 45 minutes
50 mph (80 km/h) 04 hours 36 minutes
60 mph (97 km/h) 03 hours 48 minutes
70 mph (112 km/h) 03 hours 17 minutes
75 mph (120 km/h) 03 hours 04 minutes
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