Distance Calculator

SESSION a54fa4bbbcc357065199839b64f3f7360abaec147f25fe974c94fd43a000d962

Distance from Searcy to Fayetteville

Distance between Searcy and Fayetteville is 237 kilometers (147 miles).
Driving distance from Searcy to Fayetteville is 336 kilometers (209 miles).

air 237 km
air 147 miles
car 336 km
car 209 miles

Distance Map Between Searcy and Fayetteville

Searcy, Little Rock, United StatesFayetteville, Little Rock, United States = 147 miles = 237 km.

How far is it between Searcy and Fayetteville

Searcy is located in United States with (35.2506,-91.7363) coordinates and Fayetteville is located in United States with (36.0626,-94.1574) coordinates. The calculated flying distance from Searcy to Fayetteville is equal to 147 miles which is equal to 237 km.

If you want to go by car, the driving distance between Searcy and Fayetteville is 335.75 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 02 hours 59 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 99 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Searcy 35.2506, -91.7363 35° 15´ 2.3040'' N
91° 44´ 10.5000'' W
Fayetteville 36.0626, -94.1574 36° 3´ 45.2880'' N
94° 9´ 26.7480'' W

Estimated Travel Time Between Searcy and Fayetteville

Average SpeedTravel Time
30 mph (48 km/h) 06 hours 59 minutes
40 mph (64 km/h) 05 hours 14 minutes
50 mph (80 km/h) 04 hours 11 minutes
60 mph (97 km/h) 03 hours 27 minutes
70 mph (112 km/h) 02 hours 59 minutes
75 mph (120 km/h) 02 hours 47 minutes

Please Share Your Comments