Distance Calculator

Distance from Searcy to Jacksonville

Distance between Searcy and Jacksonville is 55 kilometers (34 miles).
Driving distance from Searcy to Jacksonville is 59 kilometers (37 miles).

air 55 km
air 34 miles
car 59 km
car 37 miles

Distance Map Between Searcy and Jacksonville

Searcy, Little Rock, United StatesJacksonville, Little Rock, United States = 34 miles = 55 km.

How far is it between Searcy and Jacksonville

Searcy is located in United States with (35.2506,-91.7363) coordinates and Jacksonville is located in United States with (34.8662,-92.1102) coordinates. The calculated flying distance from Searcy to Jacksonville is equal to 34 miles which is equal to 55 km.

If you want to go by car, the driving distance between Searcy and Jacksonville is 59.11 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 31 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 4 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Searcy 35.2506, -91.7363 35° 15´ 2.3040'' N
91° 44´ 10.5000'' W
Jacksonville 34.8662, -92.1102 34° 51´ 58.3200'' N
92° 6´ 36.5400'' W

Estimated Travel Time Between Searcy and Jacksonville

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 13 minutes
40 mph (64 km/h) 00 hours 55 minutes
50 mph (80 km/h) 00 hours 44 minutes
60 mph (97 km/h) 00 hours 36 minutes
70 mph (112 km/h) 00 hours 31 minutes
75 mph (120 km/h) 00 hours 29 minutes
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