Distance Calculator

Distance from Sayreville Junction to Cranford

Distance between Sayreville Junction and Cranford is 22 kilometers (13 miles).
Driving distance from Sayreville Junction to Cranford is 28 kilometers (17 miles).

air 22 km
air 13 miles
car 28 km
car 17 miles

Distance Map Between Sayreville Junction and Cranford

Sayreville Junction, Trenton, United StatesCranford, Trenton, United States = 13 miles = 22 km.

How far is it between Sayreville Junction and Cranford

Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates and Cranford is located in United States with (40.6584,-74.2996) coordinates. The calculated flying distance from Sayreville Junction to Cranford is equal to 13 miles which is equal to 22 km.

If you want to go by car, the driving distance between Sayreville Junction and Cranford is 27.83 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 14 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 6 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sayreville Junction 40.4654, -74.3304 40° 27´ 55.3680'' N
74° 19´ 49.5480'' W
Cranford 40.6584, -74.2996 40° 39´ 30.3840'' N
74° 17´ 58.5240'' W

Estimated Travel Time Between Sayreville Junction and Cranford

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 34 minutes
40 mph (64 km/h) 00 hours 26 minutes
50 mph (80 km/h) 00 hours 20 minutes
60 mph (97 km/h) 00 hours 17 minutes
70 mph (112 km/h) 00 hours 14 minutes
75 mph (120 km/h) 00 hours 13 minutes
Please Share Your Comments