Distance Calculator

Distance from Sayreville to Cranford

Distance between Sayreville and Cranford is 23 kilometers (14 miles).
Driving distance from Sayreville to Cranford is 31 kilometers (19 miles).

air 23 km
air 14 miles
car 31 km
car 19 miles

Distance Map Between Sayreville and Cranford

Sayreville, Trenton, United StatesCranford, Trenton, United States = 14 miles = 23 km.

How far is it between Sayreville and Cranford

Sayreville is located in United States with (40.4593,-74.361) coordinates and Cranford is located in United States with (40.6584,-74.2996) coordinates. The calculated flying distance from Sayreville to Cranford is equal to 14 miles which is equal to 23 km.

If you want to go by car, the driving distance between Sayreville and Cranford is 30.81 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 16 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 8 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sayreville 40.4593, -74.361 40° 27´ 33.3720'' N
74° 21´ 39.5280'' W
Cranford 40.6584, -74.2996 40° 39´ 30.3840'' N
74° 17´ 58.5240'' W

Estimated Travel Time Between Sayreville and Cranford

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 38 minutes
40 mph (64 km/h) 00 hours 28 minutes
50 mph (80 km/h) 00 hours 23 minutes
60 mph (97 km/h) 00 hours 19 minutes
70 mph (112 km/h) 00 hours 16 minutes
75 mph (120 km/h) 00 hours 15 minutes
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