Distance Calculator

Distance from Sayreville Junction to Bloomfield

Distance between Sayreville Junction and Bloomfield is 40 kilometers (25 miles).
Driving distance from Sayreville Junction to Bloomfield is 47 kilometers (29 miles).

air 40 km
air 25 miles
car 47 km
car 29 miles

Distance Map Between Sayreville Junction and Bloomfield

Sayreville Junction, Trenton, United StatesBloomfield, Trenton, United States = 25 miles = 40 km.

How far is it between Sayreville Junction and Bloomfield

Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates and Bloomfield is located in United States with (40.8068,-74.1854) coordinates. The calculated flying distance from Sayreville Junction to Bloomfield is equal to 25 miles which is equal to 40 km.

If you want to go by car, the driving distance between Sayreville Junction and Bloomfield is 46.58 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 24 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 7 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sayreville Junction 40.4654, -74.3304 40° 27´ 55.3680'' N
74° 19´ 49.5480'' W
Bloomfield 40.8068, -74.1854 40° 48´ 24.3720'' N
74° 11´ 7.5120'' W

Estimated Travel Time Between Sayreville Junction and Bloomfield

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 58 minutes
40 mph (64 km/h) 00 hours 43 minutes
50 mph (80 km/h) 00 hours 34 minutes
60 mph (97 km/h) 00 hours 28 minutes
70 mph (112 km/h) 00 hours 24 minutes
75 mph (120 km/h) 00 hours 23 minutes
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