Distance Calculator

Distance from Wyckoff to Sayreville Junction

Distance between Wyckoff and Sayreville Junction is 62 kilometers (38 miles).
Driving distance from Wyckoff to Sayreville Junction is 77 kilometers (48 miles).

air 62 km
air 38 miles
car 77 km
car 48 miles

Distance Map Between Wyckoff and Sayreville Junction

Wyckoff, Trenton, United StatesSayreville Junction, Trenton, United States = 38 miles = 62 km.

How far is it between Wyckoff and Sayreville Junction

Wyckoff is located in United States with (41.0095,-74.1729) coordinates and Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates. The calculated flying distance from Wyckoff to Sayreville Junction is equal to 38 miles which is equal to 62 km.

If you want to go by car, the driving distance between Wyckoff and Sayreville Junction is 77.23 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 41 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 15 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Wyckoff 41.0095, -74.1729 41° 0´ 34.3440'' N
74° 10´ 22.5120'' W
Sayreville Junction 40.4654, -74.3304 40° 27´ 55.3680'' N
74° 19´ 49.5480'' W

Estimated Travel Time Between Wyckoff and Sayreville Junction

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 36 minutes
40 mph (64 km/h) 01 hours 12 minutes
50 mph (80 km/h) 00 hours 57 minutes
60 mph (97 km/h) 00 hours 47 minutes
70 mph (112 km/h) 00 hours 41 minutes
75 mph (120 km/h) 00 hours 38 minutes
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