Distance from Warrensburg to Ottawa

Distance between Warrensburg and Ottawa is 1657 kilometers (1030 miles).
Driving distance from Warrensburg to Ottawa is 1991 kilometers (1237 miles).

1657 km

1030 miles

1991 km

1237 miles

Distance Map Between Warrensburg and Ottawa

Warrensburg, Jefferson City, United States ↔ Ottawa, Ontario, Canada = 1030 miles = 1657 km.

How far is it between Warrensburg and Ottawa

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Ottawa is located in Canada with (45.4112,-75.6981) coordinates. The calculated flying distance from Warrensburg to Ottawa is equal to 1030 miles which is equal to 1657 km.

If you want to go by car, the driving distance between Warrensburg and Ottawa is 1990.81 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 17 hours 46 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 334 km.

City/Place	Latitude and Longitude	GPS Coordinates
Warrensburg	38.7628, -93.7361	38° 45´ 46.0440'' N 93° 44´ 9.7800'' W
Ottawa	45.4112, -75.6981	45° 24´ 40.2120'' N 75° 41´ 53.2320'' W

Estimated Travel Time Between Warrensburg and Ottawa

Average Speed	Travel Time
30 mph (48 km/h)	41 hours 28 minutes
40 mph (64 km/h)	31 hours 06 minutes
50 mph (80 km/h)	24 hours 53 minutes
60 mph (97 km/h)	20 hours 31 minutes
70 mph (112 km/h)	17 hours 46 minutes
75 mph (120 km/h)	16 hours 35 minutes

Warrensburg, Jefferson City, United States

Related Distances from Warrensburg

Cities	Distance
Warrensburg to Edmonton	2656 km
Warrensburg to Brampton	1531 km
Warrensburg to Hamilton	1496 km
Warrensburg to North York	1555 km
Warrensburg to Toronto	1554 km

Ottawa, Ontario, Canada

Related Distances to Ottawa

Cities	Distance
Naperville to Ottawa	1313 km
South Saint Paul to Ottawa	1643 km
Sayreville to Ottawa	730 km
Mattoon to Ottawa	1512 km
Marblehead to Ottawa	701 km