Distance Calculator

SESSION 8323e2ec2014af164f758e9a30ada26a642802d5bf0ba443f163ad7b7e2792ed

Distance from Union to Sayreville Junction

Distance between Union and Sayreville Junction is 26 kilometers (16 miles).
Driving distance from Union to Sayreville Junction is 33 kilometers (20 miles).

air 26 km
air 16 miles
car 33 km
car 20 miles

Distance Map Between Union and Sayreville Junction

Union, Trenton, United StatesSayreville Junction, Trenton, United States = 16 miles = 26 km.

How far is it between Union and Sayreville Junction

Union is located in United States with (40.6976,-74.2632) coordinates and Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates. The calculated flying distance from Union to Sayreville Junction is equal to 16 miles which is equal to 26 km.

If you want to go by car, the driving distance between Union and Sayreville Junction is 32.58 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 17 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 7 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Union 40.6976, -74.2632 40° 41´ 51.3600'' N
74° 15´ 47.5200'' W
Sayreville Junction 40.4654, -74.3304 40° 27´ 55.3680'' N
74° 19´ 49.5480'' W

Estimated Travel Time Between Union and Sayreville Junction

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 40 minutes
40 mph (64 km/h) 00 hours 30 minutes
50 mph (80 km/h) 00 hours 24 minutes
60 mph (97 km/h) 00 hours 20 minutes
70 mph (112 km/h) 00 hours 17 minutes
75 mph (120 km/h) 00 hours 16 minutes

Please Share Your Comments