Distance Calculator

Distance from Union City to Sayreville Junction

Distance between Union City and Sayreville Junction is 43 kilometers (27 miles).
Driving distance from Union City to Sayreville Junction is 51 kilometers (31 miles).

air 43 km
air 27 miles
car 51 km
car 31 miles

Distance Map Between Union City and Sayreville Junction

Union City, Trenton, United StatesSayreville Junction, Trenton, United States = 27 miles = 43 km.

How far is it between Union City and Sayreville Junction

Union City is located in United States with (40.7796,-74.0238) coordinates and Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates. The calculated flying distance from Union City to Sayreville Junction is equal to 27 miles which is equal to 43 km.

If you want to go by car, the driving distance between Union City and Sayreville Junction is 50.68 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 27 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 8 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Union City 40.7796, -74.0238 40° 46´ 46.3800'' N
74° 1´ 25.5000'' W
Sayreville Junction 40.4654, -74.3304 40° 27´ 55.3680'' N
74° 19´ 49.5480'' W

Estimated Travel Time Between Union City and Sayreville Junction

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 03 minutes
40 mph (64 km/h) 00 hours 47 minutes
50 mph (80 km/h) 00 hours 38 minutes
60 mph (97 km/h) 00 hours 31 minutes
70 mph (112 km/h) 00 hours 27 minutes
75 mph (120 km/h) 00 hours 25 minutes
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