Distance Calculator

Distance from Torrington to Seymour

Distance between Torrington and Seymour is 45 kilometers (28 miles).
Driving distance from Torrington to Seymour is 51 kilometers (32 miles).

air 45 km
air 28 miles
car 51 km
car 32 miles

Distance Map Between Torrington and Seymour

Torrington, Hartford, United StatesSeymour, Hartford, United States = 28 miles = 45 km.

How far is it between Torrington and Seymour

Torrington is located in United States with (41.8007,-73.1212) coordinates and Seymour is located in United States with (41.3968,-73.0759) coordinates. The calculated flying distance from Torrington to Seymour is equal to 28 miles which is equal to 45 km.

If you want to go by car, the driving distance between Torrington and Seymour is 50.84 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 27 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 6 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Torrington 41.8007, -73.1212 41° 48´ 2.3400'' N
73° 7´ 16.3920'' W
Seymour 41.3968, -73.0759 41° 23´ 48.3360'' N
73° 4´ 33.3840'' W

Estimated Travel Time Between Torrington and Seymour

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 03 minutes
40 mph (64 km/h) 00 hours 47 minutes
50 mph (80 km/h) 00 hours 38 minutes
60 mph (97 km/h) 00 hours 31 minutes
70 mph (112 km/h) 00 hours 27 minutes
75 mph (120 km/h) 00 hours 25 minutes
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