Distance Calculator

Distance from Seymour to Jeffersonville

Distance between Seymour and Jeffersonville is 77 kilometers (48 miles).
Driving distance from Seymour to Jeffersonville is 84 kilometers (52 miles).

air 77 km
air 48 miles
car 84 km
car 52 miles

Distance Map Between Seymour and Jeffersonville

Seymour, Indianapolis, United StatesJeffersonville, Indianapolis, United States = 48 miles = 77 km.

How far is it between Seymour and Jeffersonville

Seymour is located in United States with (38.9592,-85.8903) coordinates and Jeffersonville is located in United States with (38.2776,-85.7372) coordinates. The calculated flying distance from Seymour to Jeffersonville is equal to 48 miles which is equal to 77 km.

If you want to go by car, the driving distance between Seymour and Jeffersonville is 84.02 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 45 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 7 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seymour 38.9592, -85.8903 38° 57´ 33.1920'' N
85° 53´ 24.9000'' W
Jeffersonville 38.2776, -85.7372 38° 16´ 39.2520'' N
85° 44´ 13.8480'' W

Estimated Travel Time Between Seymour and Jeffersonville

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 45 minutes
40 mph (64 km/h) 01 hours 18 minutes
50 mph (80 km/h) 01 hours 03 minutes
60 mph (97 km/h) 00 hours 51 minutes
70 mph (112 km/h) 00 hours 45 minutes
75 mph (120 km/h) 00 hours 42 minutes
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