Distance Calculator

Distance from Seymour to Guadalupe

Distance between Seymour and Guadalupe is 1996 kilometers (1240 miles).
Driving distance from Seymour to Guadalupe is 2360 kilometers (1466 miles).

air 1996 km
air 1240 miles
car 2360 km
car 1466 miles

Distance Map Between Seymour and Guadalupe

Seymour, Indianapolis, United StatesGuadalupe, Monterrey, Mexico = 1240 miles = 1996 km.

How far is it between Seymour and Guadalupe

Seymour is located in United States with (38.9592,-85.8903) coordinates and Guadalupe is located in Mexico with (25.6768,-100.2565) coordinates. The calculated flying distance from Seymour to Guadalupe is equal to 1240 miles which is equal to 1996 km.

If you want to go by car, the driving distance between Seymour and Guadalupe is 2359.55 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 21 hours 04 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 364 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seymour 38.9592, -85.8903 38° 57´ 33.1920'' N
85° 53´ 24.9000'' W
Guadalupe 25.6768, -100.2565 25° 40´ 36.4080'' N
100° 15´ 23.2560'' W

Estimated Travel Time Between Seymour and Guadalupe

Average SpeedTravel Time
30 mph (48 km/h) 49 hours 09 minutes
40 mph (64 km/h) 36 hours 52 minutes
50 mph (80 km/h) 29 hours 29 minutes
60 mph (97 km/h) 24 hours 19 minutes
70 mph (112 km/h) 21 hours 04 minutes
75 mph (120 km/h) 19 hours 39 minutes
Please Share Your Comments