Distance from Sevastopol to Zainsk

How far is it between Sevastopol and Zainsk

Sevastopol is located in Ukraine with (44.5888,33.5224) coordinates and Zainsk is located in Russia with (55.3195,52.0694) coordinates. The calculated flying distance from Sevastopol to Zainsk is equal to 1102 miles which is equal to 1774 km.

If you want to go by car, the driving distance between Sevastopol and Zainsk is 2339.88 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 20 hours 53 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 566 km.

City/Place	Latitude and Longitude	GPS Coordinates
Sevastopol	44.5888, 33.5224	44° 35´ 19.7880'' N 33° 31´ 20.6400'' E
Zainsk	55.3195, 52.0694	55° 19´ 10.2000'' N 52° 4´ 9.9120'' E

Estimated Travel Time Between Sevastopol and Zainsk

Average Speed	Travel Time
30 mph (48 km/h)	48 hours 44 minutes
40 mph (64 km/h)	36 hours 33 minutes
50 mph (80 km/h)	29 hours 14 minutes
60 mph (97 km/h)	24 hours 07 minutes
70 mph (112 km/h)	20 hours 53 minutes
75 mph (120 km/h)	19 hours 29 minutes