Distance Calculator

Distance from Seminole to Boynton Beach

Distance between Seminole and Boynton Beach is 307 kilometers (190 miles).
Driving distance from Seminole to Boynton Beach is 385 kilometers (239 miles).

air 307 km
air 190 miles
car 385 km
car 239 miles

Distance Map Between Seminole and Boynton Beach

Seminole, Tallahassee, United StatesBoynton Beach, Tallahassee, United States = 190 miles = 307 km.

How far is it between Seminole and Boynton Beach

Seminole is located in United States with (27.8398,-82.7912) coordinates and Boynton Beach is located in United States with (26.5254,-80.0664) coordinates. The calculated flying distance from Seminole to Boynton Beach is equal to 190 miles which is equal to 307 km.

If you want to go by car, the driving distance between Seminole and Boynton Beach is 385.27 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 03 hours 26 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 78 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seminole 27.8398, -82.7912 27° 50´ 23.1000'' N
82° 47´ 28.3560'' W
Boynton Beach 26.5254, -80.0664 26° 31´ 31.2600'' N
80° 3´ 59.1480'' W

Estimated Travel Time Between Seminole and Boynton Beach

Average SpeedTravel Time
30 mph (48 km/h) 08 hours 01 minutes
40 mph (64 km/h) 06 hours 01 minutes
50 mph (80 km/h) 04 hours 48 minutes
60 mph (97 km/h) 03 hours 58 minutes
70 mph (112 km/h) 03 hours 26 minutes
75 mph (120 km/h) 03 hours 12 minutes
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