Distance from Secaucus to Sayreville Junction
Distance between Secaucus and Sayreville Junction is 43 kilometers (27 miles).
Driving distance from Secaucus to Sayreville Junction is 49 kilometers (31 miles).
43 km
27 miles
49 km
31 miles
Distance Map Between Secaucus and Sayreville Junction
Secaucus, Trenton, United States ↔ Sayreville Junction, Trenton, United States = 27 miles = 43 km.
How far is it between Secaucus and Sayreville Junction
Secaucus is located in United States with (40.7896,-74.0565) coordinates and Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates. The calculated flying distance from Secaucus to Sayreville Junction is equal to 27 miles which is equal to 43 km.
If you want to go by car, the driving distance between Secaucus and Sayreville Junction is 49.29 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 26 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 6 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Secaucus | 40.7896, -74.0565 | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
| Sayreville Junction | 40.4654, -74.3304 | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
Estimated Travel Time Between Secaucus and Sayreville Junction
| Average Speed | Travel Time |
|---|---|
| 30 mph (48 km/h) | 01 hours 01 minutes |
| 40 mph (64 km/h) | 00 hours 46 minutes |
| 50 mph (80 km/h) | 00 hours 36 minutes |
| 60 mph (97 km/h) | 00 hours 30 minutes |
| 70 mph (112 km/h) | 00 hours 26 minutes |
| 75 mph (120 km/h) | 00 hours 24 minutes |
Related Distances from Secaucus
| Cities | Distance |
|---|---|
| Secaucus to Lakewood 4 | 104 km |
| Secaucus to Elizabeth | 24 km |
| Secaucus to Hillside | 22 km |
| Secaucus to Orange 3 | 20 km |
| Secaucus to New Milford | 24 km |