Distance from Sayreville Junction to Lindenwold
Distance between Sayreville Junction and Lindenwold is 91 kilometers (57 miles).
Driving distance from Sayreville Junction to Lindenwold is 107 kilometers (67 miles).
91 km
57 miles
107 km
67 miles
Distance Map Between Sayreville Junction and Lindenwold
Sayreville Junction, Trenton, United States ↔ Lindenwold, Trenton, United States = 57 miles = 91 km.
How far is it between Sayreville Junction and Lindenwold
Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates and Lindenwold is located in United States with (39.8243,-74.9977) coordinates. The calculated flying distance from Sayreville Junction to Lindenwold is equal to 57 miles which is equal to 91 km.
If you want to go by car, the driving distance between Sayreville Junction and Lindenwold is 107.2 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 57 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 16 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Sayreville Junction | 40.4654, -74.3304 | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
| Lindenwold | 39.8243, -74.9977 | 39° 49´ 27.4080'' N 74° 59´ 51.6120'' W |
Estimated Travel Time Between Sayreville Junction and Lindenwold
| Average Speed | Travel Time |
|---|---|
| 30 mph (48 km/h) | 02 hours 14 minutes |
| 40 mph (64 km/h) | 01 hours 40 minutes |
| 50 mph (80 km/h) | 01 hours 20 minutes |
| 60 mph (97 km/h) | 01 hours 06 minutes |
| 70 mph (112 km/h) | 00 hours 57 minutes |
| 75 mph (120 km/h) | 00 hours 53 minutes |
Related Distances from Sayreville Junction
Related Distances to Lindenwold
| Cities | Distance |
|---|---|
| Hopatcong to Lindenwold | 191 km |
| Maplewood 2 to Lindenwold | 140 km |
| Fair Lawn to Lindenwold | 167 km |
| Vineland to Lindenwold | 45 km |
| Long Branch to Lindenwold | 134 km |