Distance from Sayreville Junction to Linden
Distance between Sayreville Junction and Linden is 19 kilometers (12 miles).
Driving distance from Sayreville Junction to Linden is 22 kilometers (14 miles).
19 km
12 miles
22 km
14 miles
Distance Map Between Sayreville Junction and Linden
Sayreville Junction, Trenton, United States ↔ Linden, Trenton, United States = 12 miles = 19 km.
How far is it between Sayreville Junction and Linden
Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates and Linden is located in United States with (40.6221,-74.2446) coordinates. The calculated flying distance from Sayreville Junction to Linden is equal to 12 miles which is equal to 19 km.
If you want to go by car, the driving distance between Sayreville Junction and Linden is 22.05 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 11 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 3 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Sayreville Junction | 40.4654, -74.3304 | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
| Linden | 40.6221, -74.2446 | 40° 37´ 19.3800'' N 74° 14´ 40.5240'' W |
Estimated Travel Time Between Sayreville Junction and Linden
| Average Speed | Travel Time |
|---|---|
| 30 mph (48 km/h) | 00 hours 27 minutes |
| 40 mph (64 km/h) | 00 hours 20 minutes |
| 50 mph (80 km/h) | 00 hours 16 minutes |
| 60 mph (97 km/h) | 00 hours 13 minutes |
| 70 mph (112 km/h) | 00 hours 11 minutes |
| 75 mph (120 km/h) | 00 hours 11 minutes |
Related Distances from Sayreville Junction
Related Distances to Linden
| Cities | Distance |
|---|---|
| Mahwah to Linden 2 | 67 km |
| Secaucus to Linden 2 | 29 km |
| Madison 5 to Linden 2 | 31 km |
| South Plainfield to Linden 2 | 18 km |
| South Orange to Linden 2 | 24 km |