Distance Calculator

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Distance from San Leandro to Patterson

Distance between San Leandro and Patterson is 95 kilometers (59 miles).
Driving distance from San Leandro to Patterson is 107 kilometers (66 miles).

air 95 km
air 59 miles
car 107 km
car 66 miles

Distance Map Between San Leandro and Patterson

San Leandro, Sacramento, United StatesPatterson, Sacramento, United States = 59 miles = 95 km.

How far is it between San Leandro and Patterson

San Leandro is located in United States with (37.7249,-122.1561) coordinates and Patterson is located in United States with (37.4716,-121.1297) coordinates. The calculated flying distance from San Leandro to Patterson is equal to 59 miles which is equal to 95 km.

If you want to go by car, the driving distance between San Leandro and Patterson is 107.02 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 57 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 12 km.

City/PlaceLatitude and LongitudeGPS Coordinates
San Leandro 37.7249, -122.1561 37° 43´ 29.7480'' N
122° 9´ 21.8880'' W
Patterson 37.4716, -121.1297 37° 28´ 17.7600'' N
121° 7´ 46.7760'' W

Estimated Travel Time Between San Leandro and Patterson

Average SpeedTravel Time
30 mph (48 km/h) 02 hours 13 minutes
40 mph (64 km/h) 01 hours 40 minutes
50 mph (80 km/h) 01 hours 20 minutes
60 mph (97 km/h) 01 hours 06 minutes
70 mph (112 km/h) 00 hours 57 minutes
75 mph (120 km/h) 00 hours 53 minutes

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