Distance Calculator

Distance from San Benito to Cedar Park

Distance between San Benito and Cedar Park is 487 kilometers (302 miles).
Driving distance from San Benito to Cedar Park is 566 kilometers (352 miles).

air 487 km
air 302 miles
car 566 km
car 352 miles

Distance Map Between San Benito and Cedar Park

San Benito, Austin, United StatesCedar Park, Austin, United States = 302 miles = 487 km.

How far is it between San Benito and Cedar Park

San Benito is located in United States with (26.1326,-97.6311) coordinates and Cedar Park is located in United States with (30.5052,-97.8203) coordinates. The calculated flying distance from San Benito to Cedar Park is equal to 302 miles which is equal to 487 km.

If you want to go by car, the driving distance between San Benito and Cedar Park is 566.26 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 05 hours 03 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 79 km.

City/PlaceLatitude and LongitudeGPS Coordinates
San Benito 26.1326, -97.6311 26° 7´ 57.2880'' N
97° 37´ 51.9600'' W
Cedar Park 30.5052, -97.8203 30° 30´ 18.7200'' N
97° 49´ 13.0440'' W

Estimated Travel Time Between San Benito and Cedar Park

Average SpeedTravel Time
30 mph (48 km/h) 11 hours 47 minutes
40 mph (64 km/h) 08 hours 50 minutes
50 mph (80 km/h) 07 hours 04 minutes
60 mph (97 km/h) 05 hours 50 minutes
70 mph (112 km/h) 05 hours 03 minutes
75 mph (120 km/h) 04 hours 43 minutes
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