Distance Calculator

Distance from San Angelo to Cedar Park

Distance between San Angelo and Cedar Park is 271 kilometers (169 miles).
Driving distance from San Angelo to Cedar Park is 315 kilometers (196 miles).

air 271 km
air 169 miles
car 315 km
car 196 miles

Distance Map Between San Angelo and Cedar Park

San Angelo, Austin, United StatesCedar Park, Austin, United States = 169 miles = 271 km.

How far is it between San Angelo and Cedar Park

San Angelo is located in United States with (31.4638,-100.437) coordinates and Cedar Park is located in United States with (30.5052,-97.8203) coordinates. The calculated flying distance from San Angelo to Cedar Park is equal to 169 miles which is equal to 271 km.

If you want to go by car, the driving distance between San Angelo and Cedar Park is 315.43 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 02 hours 48 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 44 km.

City/PlaceLatitude and LongitudeGPS Coordinates
San Angelo 31.4638, -100.437 31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Cedar Park 30.5052, -97.8203 30° 30´ 18.7200'' N
97° 49´ 13.0440'' W

Estimated Travel Time Between San Angelo and Cedar Park

Average SpeedTravel Time
30 mph (48 km/h) 06 hours 34 minutes
40 mph (64 km/h) 04 hours 55 minutes
50 mph (80 km/h) 03 hours 56 minutes
60 mph (97 km/h) 03 hours 15 minutes
70 mph (112 km/h) 02 hours 48 minutes
75 mph (120 km/h) 02 hours 37 minutes
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