Distance from San Angelo to Victoria

Distance between San Angelo and Victoria is 443 kilometers (275 miles).
Driving distance from San Angelo to Victoria is 528 kilometers (328 miles).

443 km

275 miles

528 km

328 miles

Distance Map Between San Angelo and Victoria

San Angelo, Austin, United States ↔ Victoria, Austin, United States = 275 miles = 443 km.

How far is it between San Angelo and Victoria

San Angelo is located in United States with (31.4638,-100.437) coordinates and Victoria is located in United States with (28.8053,-97.0036) coordinates. The calculated flying distance from San Angelo to Victoria is equal to 275 miles which is equal to 443 km.

If you want to go by car, the driving distance between San Angelo and Victoria is 527.92 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 04 hours 42 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 85 km.

City/Place	Latitude and Longitude	GPS Coordinates
San Angelo	31.4638, -100.437	31° 27´ 49.5720'' N 100° 26´ 13.3440'' W
Victoria	28.8053, -97.0036	28° 48´ 18.9720'' N 97° 0´ 12.9600'' W

Estimated Travel Time Between San Angelo and Victoria

Average Speed	Travel Time
30 mph (48 km/h)	10 hours 59 minutes
40 mph (64 km/h)	08 hours 14 minutes
50 mph (80 km/h)	06 hours 35 minutes
60 mph (97 km/h)	05 hours 26 minutes
70 mph (112 km/h)	04 hours 42 minutes
75 mph (120 km/h)	04 hours 23 minutes

San Angelo, Austin, United States

Related Distances from San Angelo

Cities	Distance
San Angelo to Pharr	720 km
San Angelo to The Colony	432 km
San Angelo to North Richland Hills	379 km
San Angelo to Lewisville	418 km
San Angelo to Port Arthur	732 km

Victoria, Austin, United States

Related Distances to Victoria

Cities	Distance
Odessa 2 to Victoria 3	734 km
El Paso to Victoria 3	1071 km
Hereford 2 to Victoria 3	969 km
San Angelo to Victoria 3	528 km
Lubbock to Victoria 3	806 km