Distance Calculator

Distance from Saint Charles to Clayton

Distance between Saint Charles and Clayton is 21 kilometers (13 miles).
Driving distance from Saint Charles to Clayton is 35 kilometers (22 miles).

air 21 km
air 13 miles
car 35 km
car 22 miles

Distance Map Between Saint Charles and Clayton

Saint Charles, Jefferson City, United StatesClayton, Jefferson City, United States = 13 miles = 21 km.

How far is it between Saint Charles and Clayton

Saint Charles is located in United States with (38.7839,-90.4812) coordinates and Clayton is located in United States with (38.6426,-90.3237) coordinates. The calculated flying distance from Saint Charles to Clayton is equal to 13 miles which is equal to 21 km.

If you want to go by car, the driving distance between Saint Charles and Clayton is 34.88 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 18 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 14 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Saint Charles 38.7839, -90.4812 38° 47´ 2.1840'' N
90° 28´ 52.4280'' W
Clayton 38.6426, -90.3237 38° 38´ 33.1800'' N
90° 19´ 25.4280'' W

Estimated Travel Time Between Saint Charles and Clayton

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 43 minutes
40 mph (64 km/h) 00 hours 32 minutes
50 mph (80 km/h) 00 hours 26 minutes
60 mph (97 km/h) 00 hours 21 minutes
70 mph (112 km/h) 00 hours 18 minutes
75 mph (120 km/h) 00 hours 17 minutes
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