Distance Calculator

Distance from Reynoldsburg to Pickerington

Distance between Reynoldsburg and Pickerington is 9 kilometers (6 miles).
Driving distance from Reynoldsburg to Pickerington is 10 kilometers (6 miles).

air 9 km
air 6 miles
car 10 km
car 6 miles

Distance Map Between Reynoldsburg and Pickerington

Reynoldsburg, Columbus, United StatesPickerington, Columbus, United States = 6 miles = 9 km.

How far is it between Reynoldsburg and Pickerington

Reynoldsburg is located in United States with (39.9548,-82.8121) coordinates and Pickerington is located in United States with (39.8842,-82.7535) coordinates. The calculated flying distance from Reynoldsburg to Pickerington is equal to 6 miles which is equal to 9 km.

If you want to go by car, the driving distance between Reynoldsburg and Pickerington is 10.35 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 05 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 1 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Reynoldsburg 39.9548, -82.8121 39° 57´ 17.2440'' N
82° 48´ 43.6320'' W
Pickerington 39.8842, -82.7535 39° 53´ 3.2280'' N
82° 45´ 12.6000'' W

Estimated Travel Time Between Reynoldsburg and Pickerington

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 12 minutes
40 mph (64 km/h) 00 hours 09 minutes
50 mph (80 km/h) 00 hours 07 minutes
60 mph (97 km/h) 00 hours 06 minutes
70 mph (112 km/h) 00 hours 05 minutes
75 mph (120 km/h) 00 hours 05 minutes
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