Distance Calculator

Distance from Oranienburg to Schwedt (Oder)

Distance between Oranienburg and Schwedt (Oder) is 77 kilometers (48 miles).
Driving distance from Oranienburg to Schwedt (Oder) is 92 kilometers (57 miles).

air 77 km
air 48 miles
car 92 km
car 57 miles

Distance Map Between Oranienburg and Schwedt (Oder)

Oranienburg, Potsdam, GermanySchwedt (Oder), Potsdam, Germany = 48 miles = 77 km.

How far is it between Oranienburg and Schwedt (Oder)

Oranienburg is located in Germany with (52.7558,13.242) coordinates and Schwedt (Oder) is located in Germany with (53.0596,14.2815) coordinates. The calculated flying distance from Oranienburg to Schwedt (Oder) is equal to 48 miles which is equal to 77 km.

If you want to go by car, the driving distance between Oranienburg and Schwedt (Oder) is 92.42 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 49 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 15 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Oranienburg 52.7558, 13.242 52° 45´ 20.7720'' N
13° 14´ 31.0920'' E
Schwedt (Oder) 53.0596, 14.2815 53° 3´ 34.6680'' N
14° 16´ 53.5440'' E

Estimated Travel Time Between Oranienburg and Schwedt (Oder)

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 55 minutes
40 mph (64 km/h) 01 hours 26 minutes
50 mph (80 km/h) 01 hours 09 minutes
60 mph (97 km/h) 00 hours 57 minutes
70 mph (112 km/h) 00 hours 49 minutes
75 mph (120 km/h) 00 hours 46 minutes
Please Share Your Comments