Distance from Long Beach to Tecamac de Felipe Villanueva
Distance between Long Beach and Tecamac de Felipe Villanueva is 2459 kilometers (1528 miles).
Driving distance from Long Beach to Tecamac de Felipe Villanueva is 2938 kilometers (1826 miles).
2459 km
1528 miles
2938 km
1826 miles
Distance Map Between Long Beach and Tecamac de Felipe Villanueva
Long Beach, Sacramento, United States ↔ Tecamac de Felipe Villanueva, Cuernavaca, Mexico = 1528 miles = 2459 km.
How far is it between Long Beach and Tecamac de Felipe Villanueva
Long Beach is located in United States with (33.767,-118.1892) coordinates and Tecamac de Felipe Villanueva is located in Mexico with (19.7129,-98.969) coordinates. The calculated flying distance from Long Beach to Tecamac de Felipe Villanueva is equal to 1528 miles which is equal to 2459 km.
If you want to go by car, the driving distance between Long Beach and Tecamac de Felipe Villanueva is 2938.27 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 26 hours 14 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 479 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Long Beach | 33.767, -118.1892 | 33° 46´ 1.0560'' N 118° 11´ 21.2280'' W |
| Tecamac de Felipe Villanueva | 19.7129, -98.969 | 19° 42´ 46.3680'' N 98° 58´ 8.2200'' W |
Estimated Travel Time Between Long Beach and Tecamac de Felipe Villanueva
| Average Speed | Travel Time |
|---|---|
| 30 mph (48 km/h) | 61 hours 12 minutes |
| 40 mph (64 km/h) | 45 hours 54 minutes |
| 50 mph (80 km/h) | 36 hours 43 minutes |
| 60 mph (97 km/h) | 30 hours 17 minutes |
| 70 mph (112 km/h) | 26 hours 14 minutes |
| 75 mph (120 km/h) | 24 hours 29 minutes |
Related Distances from Long Beach
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|---|---|
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