Distance Calculator

Distance from Jacksonville to Tecamac de Felipe Villanueva

Distance between Jacksonville and Tecamac de Felipe Villanueva is 2102 kilometers (1306 miles).
Driving distance from Jacksonville to Tecamac de Felipe Villanueva is 2998 kilometers (1863 miles).

air 2102 km
air 1306 miles
car 2998 km
car 1863 miles

Distance Map Between Jacksonville and Tecamac de Felipe Villanueva

Jacksonville, Tallahassee, United StatesTecamac de Felipe Villanueva, Toluca, Mexico = 1306 miles = 2102 km.

How far is it between Jacksonville and Tecámac de Felipe Villanueva

Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Tecamac de Felipe Villanueva is located in Mexico with (19.7131,-98.9683) coordinates. The calculated flying distance from Jacksonville to Tecamac de Felipe Villanueva is equal to 1306 miles which is equal to 2102 km.

If you want to go by car, the driving distance between Jacksonville and Tecamac de Felipe Villanueva is 2998.13 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 26 hours 46 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 896 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Jacksonville 30.3322, -81.6557 30° 19´ 55.8480'' N
81° 39´ 20.3400'' W
Tecamac de Felipe Villanueva 19.7131, -98.9683 19° 42´ 47.0160'' N
98° 58´ 5.9880'' W

Estimated Travel Time Between Jacksonville and Tecámac de Felipe Villanueva

Average SpeedTravel Time
30 mph (48 km/h) 62 hours 27 minutes
40 mph (64 km/h) 46 hours 50 minutes
50 mph (80 km/h) 37 hours 28 minutes
60 mph (97 km/h) 30 hours 54 minutes
70 mph (112 km/h) 26 hours 46 minutes
75 mph (120 km/h) 24 hours 59 minutes
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