Distance Calculator

Distance from Jacksonville to San Antonio de la Cal

Distance between Jacksonville and San Antonio de la Cal is 2125 kilometers (1321 miles).
Driving distance from Jacksonville to San Antonio de la Cal is 3268 kilometers (2031 miles).

air 2125 km
air 1321 miles
car 3268 km
car 2031 miles

Distance Map Between Jacksonville and San Antonio de la Cal

Jacksonville, Tallahassee, United StatesSan Antonio de la Cal, Oaxaca de Juarez, Mexico = 1321 miles = 2125 km.

How far is it between Jacksonville and San Antonio de la Cal

Jacksonville is located in United States with (30.3322,-81.6557) coordinates and San Antonio de la Cal is located in Mexico with (17.0283,-96.7006) coordinates. The calculated flying distance from Jacksonville to San Antonio de la Cal is equal to 1321 miles which is equal to 2125 km.

If you want to go by car, the driving distance between Jacksonville and San Antonio de la Cal is 3268.27 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 29 hours 10 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 1143 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Jacksonville 30.3322, -81.6557 30° 19´ 55.8480'' N
81° 39´ 20.3400'' W
San Antonio de la Cal 17.0283, -96.7006 17° 1´ 41.9880'' N
96° 42´ 2.0160'' W

Estimated Travel Time Between Jacksonville and San Antonio de la Cal

Average SpeedTravel Time
30 mph (48 km/h) 68 hours 05 minutes
40 mph (64 km/h) 51 hours 04 minutes
50 mph (80 km/h) 40 hours 51 minutes
60 mph (97 km/h) 33 hours 41 minutes
70 mph (112 km/h) 29 hours 10 minutes
75 mph (120 km/h) 27 hours 14 minutes
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