Distance Calculator

Distance from Belgrade to Chateauroux

Distance between Belgrade and Chateauroux is 1468 kilometers (912 miles).
Driving distance from Belgrade to Chateauroux is 1811 kilometers (1125 miles).

air 1468 km
air 912 miles
car 1811 km
car 1125 miles

Distance Map Between Belgrade and Chateauroux

Belgrade, SerbiaChateauroux, Orleans, France = 912 miles = 1468 km.

How far is it between Belgrade and Châteauroux

Belgrade is located in Serbia with (44.804,20.4651) coordinates and Chateauroux is located in France with (46.8167,1.7) coordinates. The calculated flying distance from Belgrade to Chateauroux is equal to 912 miles which is equal to 1468 km.

If you want to go by car, the driving distance between Belgrade and Chateauroux is 1811.25 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 16 hours 10 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 343 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Belgrade 44.804, 20.4651 44° 48´ 14.4360'' N
20° 27´ 54.4680'' E
Chateauroux 46.8167, 1.7 46° 49´ 0.0120'' N
1° 42´ 0.0000'' E

Estimated Travel Time Between Belgrade and Châteauroux

Average SpeedTravel Time
30 mph (48 km/h) 37 hours 44 minutes
40 mph (64 km/h) 28 hours 18 minutes
50 mph (80 km/h) 22 hours 38 minutes
60 mph (97 km/h) 18 hours 40 minutes
70 mph (112 km/h) 16 hours 10 minutes
75 mph (120 km/h) 15 hours 05 minutes
Chateauroux, Orleans, France

Related Distances to Chateauroux

CitiesDistance
Belgrade to Chateauroux1811 km
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