Distance from Belgrade to Chateauroux

Distance between Belgrade and Chateauroux is 1468 kilometers (912 miles).
Driving distance from Belgrade to Chateauroux is 1811 kilometers (1125 miles).

1468 km

912 miles

1811 km

1125 miles

Distance Map Between Belgrade and Chateauroux

Belgrade, Serbia ↔ Chateauroux, Orleans, France = 912 miles = 1468 km.

How far is it between Belgrade and Châteauroux

Belgrade is located in Serbia with (44.804,20.4651) coordinates and Chateauroux is located in France with (46.8167,1.7) coordinates. The calculated flying distance from Belgrade to Chateauroux is equal to 912 miles which is equal to 1468 km.

If you want to go by car, the driving distance between Belgrade and Chateauroux is 1811.25 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 16 hours 10 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 343 km.

City/Place	Latitude and Longitude	GPS Coordinates
Belgrade	44.804, 20.4651	44° 48´ 14.4360'' N 20° 27´ 54.4680'' E
Chateauroux	46.8167, 1.7	46° 49´ 0.0120'' N 1° 42´ 0.0000'' E

Estimated Travel Time Between Belgrade and Châteauroux

Average Speed	Travel Time
30 mph (48 km/h)	37 hours 44 minutes
40 mph (64 km/h)	28 hours 18 minutes
50 mph (80 km/h)	22 hours 38 minutes
60 mph (97 km/h)	18 hours 40 minutes
70 mph (112 km/h)	16 hours 10 minutes
75 mph (120 km/h)	15 hours 05 minutes

Belgrade, Serbia

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Belgrade to Agde	1708 km
Belgrade to Aix En Provence	1500 km
Belgrade to Aix Les Bains	1370 km
Belgrade to Ajaccio	1429 km
Belgrade to Albertville 2	1341 km
Belgrade to Albi	1846 km
Belgrade to Ales	1630 km
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Chateauroux, Orleans, France

Related Distances to Chateauroux

Cities	Distance
Belgrade to Chateauroux	1811 km