Distance Calculator

Distance from Ararangua to Chapeco

Distance between Ararangua and Chapeco is 368 kilometers (229 miles).
Driving distance from Ararangua to Chapeco is 488 kilometers (303 miles).

air 368 km
air 229 miles
car 488 km
car 303 miles

Distance Map Between Ararangua and Chapeco

Ararangua, Florianopolis, BrazilChapeco, Florianopolis, Brazil = 229 miles = 368 km.

How far is it between Araranguá and Chapecó

Ararangua is located in Brazil with (-28.9358,-49.4954) coordinates and Chapeco is located in Brazil with (-27.0964,-52.6183) coordinates. The calculated flying distance from Ararangua to Chapeco is equal to 229 miles which is equal to 368 km.

If you want to go by car, the driving distance between Ararangua and Chapeco is 487.93 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 04 hours 21 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 120 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Ararangua -28.9358, -49.4954 28° 56´ 8.7000'' S
49° 29´ 43.3680'' W
Chapeco -27.0964, -52.6183 27° 5´ 47.0040'' S
52° 37´ 5.9880'' W

Estimated Travel Time Between Araranguá and Chapecó

Average SpeedTravel Time
30 mph (48 km/h) 10 hours 09 minutes
40 mph (64 km/h) 07 hours 37 minutes
50 mph (80 km/h) 06 hours 05 minutes
60 mph (97 km/h) 05 hours 01 minutes
70 mph (112 km/h) 04 hours 21 minutes
75 mph (120 km/h) 04 hours 03 minutes
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