Distance Calculator

Distance from Westerville to Sandusky

Distance between Westerville and Sandusky is 148 kilometers (92 miles).
Driving distance from Westerville to Sandusky is 163 kilometers (101 miles).

air 148 km
air 92 miles
car 163 km
car 101 miles

Distance Map Between Westerville and Sandusky

Westerville, Columbus, United StatesSandusky, Columbus, United States = 92 miles = 148 km.

How far is it between Westerville and Sandusky

Westerville is located in United States with (40.1262,-82.9291) coordinates and Sandusky is located in United States with (41.4489,-82.708) coordinates. The calculated flying distance from Westerville to Sandusky is equal to 92 miles which is equal to 148 km.

If you want to go by car, the driving distance between Westerville and Sandusky is 162.58 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 27 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 15 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Westerville 40.1262, -82.9291 40° 7´ 34.2120'' N
82° 55´ 44.6520'' W
Sandusky 41.4489, -82.708 41° 26´ 56.1840'' N
82° 42´ 28.6560'' W

Estimated Travel Time Between Westerville and Sandusky

Average SpeedTravel Time
30 mph (48 km/h) 03 hours 23 minutes
40 mph (64 km/h) 02 hours 32 minutes
50 mph (80 km/h) 02 hours 01 minutes
60 mph (97 km/h) 01 hours 40 minutes
70 mph (112 km/h) 01 hours 27 minutes
75 mph (120 km/h) 01 hours 21 minutes
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