Distance Calculator

Distance from Walnut to Victorville

Distance between Walnut and Victorville is 78 kilometers (48 miles).
Driving distance from Walnut to Victorville is 106 kilometers (66 miles).

air 78 km
air 48 miles
car 106 km
car 66 miles

Distance Map Between Walnut and Victorville

Walnut, Sacramento, United StatesVictorville, Sacramento, United States = 48 miles = 78 km.

How far is it between Walnut and Victorville

Walnut is located in United States with (34.0203,-117.8653) coordinates and Victorville is located in United States with (34.5361,-117.2912) coordinates. The calculated flying distance from Walnut to Victorville is equal to 48 miles which is equal to 78 km.

If you want to go by car, the driving distance between Walnut and Victorville is 105.87 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 56 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 28 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Walnut 34.0203, -117.8653 34° 1´ 13.0440'' N
117° 51´ 55.2240'' W
Victorville 34.5361, -117.2912 34° 32´ 9.9960'' N
117° 17´ 28.1760'' W

Estimated Travel Time Between Walnut and Victorville

Average SpeedTravel Time
30 mph (48 km/h) 02 hours 12 minutes
40 mph (64 km/h) 01 hours 39 minutes
50 mph (80 km/h) 01 hours 19 minutes
60 mph (97 km/h) 01 hours 05 minutes
70 mph (112 km/h) 00 hours 56 minutes
75 mph (120 km/h) 00 hours 52 minutes
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