Distance Calculator

Distance from Walnut Park to Victorville

Distance between Walnut Park and Victorville is 107 kilometers (66 miles).
Driving distance from Walnut Park to Victorville is 143 kilometers (89 miles).

air 107 km
air 66 miles
car 143 km
car 89 miles

Distance Map Between Walnut Park and Victorville

Walnut Park, Sacramento, United StatesVictorville, Sacramento, United States = 66 miles = 107 km.

How far is it between Walnut Park and Victorville

Walnut Park is located in United States with (33.9681,-118.2251) coordinates and Victorville is located in United States with (34.5361,-117.2912) coordinates. The calculated flying distance from Walnut Park to Victorville is equal to 66 miles which is equal to 107 km.

If you want to go by car, the driving distance between Walnut Park and Victorville is 142.94 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 16 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 36 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Walnut Park 33.9681, -118.2251 33° 58´ 5.0520'' N
118° 13´ 30.2520'' W
Victorville 34.5361, -117.2912 34° 32´ 9.9960'' N
117° 17´ 28.1760'' W

Estimated Travel Time Between Walnut Park and Victorville

Average SpeedTravel Time
30 mph (48 km/h) 02 hours 58 minutes
40 mph (64 km/h) 02 hours 14 minutes
50 mph (80 km/h) 01 hours 47 minutes
60 mph (97 km/h) 01 hours 28 minutes
70 mph (112 km/h) 01 hours 16 minutes
75 mph (120 km/h) 01 hours 11 minutes
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