Distance Calculator

Distance from Tinley Park to Jacksonville

Distance between Tinley Park and Jacksonville is 290 kilometers (180 miles).
Driving distance from Tinley Park to Jacksonville is 347 kilometers (216 miles).

air 290 km
air 180 miles
car 347 km
car 216 miles

Distance Map Between Tinley Park and Jacksonville

Tinley Park, Springfield, United StatesJacksonville, Springfield, United States = 180 miles = 290 km.

How far is it between Tinley Park and Jacksonville

Tinley Park is located in United States with (41.5734,-87.7845) coordinates and Jacksonville is located in United States with (39.7339,-90.229) coordinates. The calculated flying distance from Tinley Park to Jacksonville is equal to 180 miles which is equal to 290 km.

If you want to go by car, the driving distance between Tinley Park and Jacksonville is 347.2 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 03 hours 06 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 57 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Tinley Park 41.5734, -87.7845 41° 34´ 24.1320'' N
87° 47´ 4.1640'' W
Jacksonville 39.7339, -90.229 39° 44´ 2.1840'' N
90° 13´ 44.4360'' W

Estimated Travel Time Between Tinley Park and Jacksonville

Average SpeedTravel Time
30 mph (48 km/h) 07 hours 14 minutes
40 mph (64 km/h) 05 hours 25 minutes
50 mph (80 km/h) 04 hours 20 minutes
60 mph (97 km/h) 03 hours 34 minutes
70 mph (112 km/h) 03 hours 06 minutes
75 mph (120 km/h) 02 hours 53 minutes
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