Distance Calculator

Distance from Seven Oaks to Lexington

Distance between Seven Oaks and Lexington is 11 kilometers (7 miles).
Driving distance from Seven Oaks to Lexington is 17 kilometers (10 miles).

air 11 km
air 7 miles
car 17 km
car 10 miles

Distance Map Between Seven Oaks and Lexington

Seven Oaks, Columbia, United StatesLexington, Columbia, United States = 7 miles = 11 km.

How far is it between Seven Oaks and Lexington

Seven Oaks is located in United States with (34.0488,-81.1465) coordinates and Lexington is located in United States with (33.9815,-81.2362) coordinates. The calculated flying distance from Seven Oaks to Lexington is equal to 7 miles which is equal to 11 km.

If you want to go by car, the driving distance between Seven Oaks and Lexington is 16.79 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 08 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 6 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seven Oaks 34.0488, -81.1465 34° 2´ 55.5360'' N
81° 8´ 47.3280'' W
Lexington 33.9815, -81.2362 33° 58´ 53.5440'' N
81° 14´ 10.3560'' W

Estimated Travel Time Between Seven Oaks and Lexington

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 20 minutes
40 mph (64 km/h) 00 hours 15 minutes
50 mph (80 km/h) 00 hours 12 minutes
60 mph (97 km/h) 00 hours 10 minutes
70 mph (112 km/h) 00 hours 08 minutes
75 mph (120 km/h) 00 hours 08 minutes
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