Distance Calculator

Distance from Secaucus to Lindenwold

Distance between Secaucus and Lindenwold is 134 kilometers (83 miles).
Driving distance from Secaucus to Lindenwold is 146 kilometers (91 miles).

air 134 km
air 83 miles
car 146 km
car 91 miles

Distance Map Between Secaucus and Lindenwold

Secaucus, Trenton, United StatesLindenwold, Trenton, United States = 83 miles = 134 km.

How far is it between Secaucus and Lindenwold

Secaucus is located in United States with (40.7896,-74.0565) coordinates and Lindenwold is located in United States with (39.8243,-74.9977) coordinates. The calculated flying distance from Secaucus to Lindenwold is equal to 83 miles which is equal to 134 km.

If you want to go by car, the driving distance between Secaucus and Lindenwold is 146.29 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 18 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 12 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Secaucus 40.7896, -74.0565 40° 47´ 22.3800'' N
74° 3´ 23.5080'' W
Lindenwold 39.8243, -74.9977 39° 49´ 27.4080'' N
74° 59´ 51.6120'' W

Estimated Travel Time Between Secaucus and Lindenwold

Average SpeedTravel Time
30 mph (48 km/h) 03 hours 02 minutes
40 mph (64 km/h) 02 hours 17 minutes
50 mph (80 km/h) 01 hours 49 minutes
60 mph (97 km/h) 01 hours 30 minutes
70 mph (112 km/h) 01 hours 18 minutes
75 mph (120 km/h) 01 hours 13 minutes
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