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Distance from Seaford to Copiague

Distance between Seaford and Copiague is 8 kilometers (5 miles).
Driving distance from Seaford to Copiague is 9 kilometers (5 miles).

air 8 km
air 5 miles
car 9 km
car 5 miles

Distance Map Between Seaford and Copiague

Seaford, Albany, United StatesCopiague, Albany, United States = 5 miles = 8 km.

How far is it between Seaford and Copiague

Seaford is located in United States with (40.6659,-73.4882) coordinates and Copiague is located in United States with (40.6815,-73.3998) coordinates. The calculated flying distance from Seaford to Copiague is equal to 5 miles which is equal to 8 km.

If you want to go by car, the driving distance between Seaford and Copiague is 8.8 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 04 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 1 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seaford 40.6659, -73.4882 40° 39´ 57.3480'' N
73° 29´ 17.4480'' W
Copiague 40.6815, -73.3998 40° 40´ 53.3640'' N
73° 23´ 59.4240'' W

Estimated Travel Time Between Seaford and Copiague

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 11 minutes
40 mph (64 km/h) 00 hours 08 minutes
50 mph (80 km/h) 00 hours 06 minutes
60 mph (97 km/h) 00 hours 05 minutes
70 mph (112 km/h) 00 hours 04 minutes
75 mph (120 km/h) 00 hours 04 minutes

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